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1000 Post give away and the winner is..........

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  • Type2Type2 Posts: 13,985 ✭✭✭✭✭
    900


    Hoard the keys.
  • ponderitponderit Posts: 1,544 ✭✭✭✭✭
    1973 Halves? Thanks for the chance
    Successful BST transactions with Rob41281, crazyhounddog, Commoncents, CarlWohlford, blu62vette, Manofcoins, Monstarcoins, coinlietenant, iconbuster, RWW,Nolawyer, NewParadigm, Flatwoods, papabear, Yellowkid, Ankur, Pccoins, tlake22, drddm, Connecticoin, Cladiator, lkeigwin, pursuitofliberty
  • AgBloxAgBlox Posts: 744 ✭✭
    1592
  • 851 halves

    Thanks for the chance
  • 903 half dollars.
    image
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  • I will renew my guess to 1631 Kennedy Halfs.

    Regards, Larryimage
  • N 45°15’ E

    and there are no halves in the jar.
  • adamlaneusadamlaneus Posts: 6,969 ✭✭✭
    The equation that relates perimeter to radius is: perimeter = (2*pi*radius)
    Arc length is the length along a curve. The arc length of a full circle is the perimeter.

    A curve such as this can be modelled with two circles. An inner one and an outer one. Both circles have the same centerpoint. These two circles differ by a radius of 60 feet.

    If I substitute "deltaR" for "r", I can convert to an equation that relates how much perimeter difference there will be between two circles of a certain radius difference.
    The radius difference we know is 60 feet.
    One could also set up two circle equations and subtract them and you'll see how I can substitute (deltaR for r1 - r2) and (deltaPerimeter for p1 - p2)

    So, for a full circle (360 degrees), the difference between the inner and outer arc lengths are 2*pi*60. 376.991 feet.

    Subtract the two values given for arc length (174.533 from 195.477). The arc length difference given is 20.944.

    Take the ratio of the full circle perimeter difference to the known perimeter difference.
    376.991 / 20.944 = 1/18

    The road traces out 1/18th of a circle.

    1/18th of a circle is 20 degrees. So the curve exits 20 degrees to the right of the original bearing.

    Enters at N 45°15’ E
    Exits at N 65°15’ E



    Do I have to do the other one?
    I don't recognize the jar. Wonder how many ounces it held. Average pretzel density...hm...coin stacking...
  • We now have two names in the hat for getting the bearing correct, but no one has correctly identified how many coins are in the jug. One person is very close, but not perfect.

    Last Hint: if the number of coins is this year, then we just lost Sonny Bono, Jack Lord and Harry Caray, but we gained Elle Fanning; Exxon buys Mobil; John Glenn flies again; Henry Hyde has 81 questions for Bill clinton about Monica Lewinsky. I will bet number 82 was what's her phone number.

    Jim

    image
  • AgBloxAgBlox Posts: 744 ✭✭
    1998 image
  • speetyspeety Posts: 5,424
    1998

    image
    Want to buy an auction catalog for the William Hesslein Sale (December 2, 1926). Thanks to all those who have helped us obtain the others!!!

  • 1998 Kennedy halves.

    Or maybe 998 kennedy halves.
    image
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  • lkeigwinlkeigwin Posts: 16,893 ✭✭✭✭✭
    I'll guess 996 halves. Thanks for the chance!
    Lance.

    Jennifer Flowers, when asked if her experience with Clinton was much like Monika Lewinski's, said "close, but no cigar". image
  • I don't have the patience to figure out the first question so I'll guess $541 in halves.
  • gsa1fangsa1fan Posts: 5,566 ✭✭✭
    896 Kennedy half dollars
    Avid collector of GSA's.
  • DBSTrader2DBSTrader2 Posts: 3,498 ✭✭✭✭
    1998
  • 456 - 50 cent piecesimage
    Ilikacoinsawholebuncha
  • ElmerFusterpuckElmerFusterpuck Posts: 4,795 ✭✭✭✭✭
    based on your last hint, I'll jump in the 1998 pile.
  • ponderitponderit Posts: 1,544 ✭✭✭✭✭
    1998... I tried to put the Portland Cement clue to good use, but no cigar! Thanks again for the chance!

    Edited for spellingimage
    Successful BST transactions with Rob41281, crazyhounddog, Commoncents, CarlWohlford, blu62vette, Manofcoins, Monstarcoins, coinlietenant, iconbuster, RWW,Nolawyer, NewParadigm, Flatwoods, papabear, Yellowkid, Ankur, Pccoins, tlake22, drddm, Connecticoin, Cladiator, lkeigwin, pursuitofliberty
  • ClosedLoopClosedLoop Posts: 1,077 ✭✭✭
    1997
    figglehorn
  • 1998 is my answer after that clue

    ....but the cement bag one was wrong then cause i came up with 982
    47lbs x .5295=24.886

    24.886lbs=11288.32726g

    11288.32726g/12.5g=981.59 half dollars
  • Kennedy half link

    one coin weighs 11.3 grams +/-

    weight conversion

    11.3 gram = 0.00026502378326 bag [portland cement]

    1998 x 0.00026502378326 = 0.5295 bag [portland cement]

    Yes, I have a lot of time on my hands. This place is keeping me out of trouble.

  • Yes, the work is over; everyone can now pile on. Both answers are visible.

    N 65 15 E : Speety and Adam

    1998 or $999.00

    Remember this post?

    I had just finished searching two boxes of Kennedys for silver; these two coins were on my desk not in the jug when I took the pictures.

    WARNING:
    image
    Film at 11.image
  • adamlaneusadamlaneus Posts: 6,969 ✭✭✭
    image
  • ponderitponderit Posts: 1,544 ✭✭✭✭✭
    Adam, please tell me Ms. Gill didn't win that suit....
    Successful BST transactions with Rob41281, crazyhounddog, Commoncents, CarlWohlford, blu62vette, Manofcoins, Monstarcoins, coinlietenant, iconbuster, RWW,Nolawyer, NewParadigm, Flatwoods, papabear, Yellowkid, Ankur, Pccoins, tlake22, drddm, Connecticoin, Cladiator, lkeigwin, pursuitofliberty
  • Adam, is that a threat? I said the coin was fake.image
  • I do like how the jar states "individually twisted".

  • Go Steelers; whip those Baltimore Brown Stains.
  • jdillanejdillane Posts: 2,365 ✭✭✭
    866 halves.

    Thx!
  • ......iceman0xh.

    Welcome to the boards. PM me your address and I will send you the coin and tokens.
  • thank ya sir, I am glad to have found this forum site

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