Can't. In one of the 8 or so states that doesn't do Powerball.
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That was precisely what I was going to reply with, what are the odds of that? 1 in 175,223,510 are the current odds. Your chances would be pretty good if you purchased 175,223,510 different combinations. Is it possible to buy that many? How could one accomplish this?
This HAS BEEN DONE in other lotteries. Naturally the groups are private, but there was a group that won this way in the Netherlands or some country like that.
NOTE: In the powerball you have to buy "in person" in most places, possibly all, so buying more than a few thousand tickets would be impossible due to time constraints.
Also remember that if you SPLIT THE WINNINGS you are going to be hating life after spending $300M+
<< <i>You also can't lose anything you would remember in a week if you play >>
A week later? I'm sure I would remember buying a ticket. And if you wouldn't remember, what good would having the winning ticket be, anyway?
<< <i>$2 is never going to be noticed by the people on this board. >>
In that case, it shouldn't be a problem to get everybody on the board to send me $2, should it? The odds of getting anything back aren't significantly worse, yet somehow, I doubt there will be a flood of money in my mailbox anytime soon.
That was precisely what I was going to reply with, what are the odds of that? 1 in 175,223,510 are the current odds. Your chances would be pretty good if you purchased 175,223,510 different combinations. Is it possible to buy that many? How could one accomplish this? >>
It could be possible to do it, but you'd need quite the taskforce to accomplish it. The new machines which let you buy a ticket without having to go up to the counter at a gas station/etc. have a maximum of $20 per ticket and I'll make a generous round-trip estimate of 10 seconds to insert the $20 and receive the ticket at the end with 10 numbers. This would take approximately 200 years to buy, assuming working 24/7 at this rate and the machines don't run out of paper.
However, the Birthday Paradox falls into play here with randomly picked numbers - you'll end up receiving duplicate picks with this volume. To ensure you don't miss any number and don't overspend, the automated machines are out of the question: you would have to pre-select each combination manually.
Assuming you can counter all of the hurdles associated with the practical execution of these ticket purchases, as the tickets are $2 per pick, that would cost you $350,447,020 to cover all 175,223,510 combinations. At a $550 million jackpot, that would be a pre-tax profit of $199,552,980 only if no one else wins. If one other person gets it, you'll split the pot and would then have lost $75,447,020.
So, I'd recommend against it
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<< <i>You also can't lose anything you would remember in a week if you play >>
A week later? I'm sure I would remember buying a ticket. And if you wouldn't remember, what good would having the winning ticket be, anyway?
<< <i>$2 is never going to be noticed by the people on this board. >>
In that case, it shouldn't be a problem to get everybody on the board to send me $2, should it? The odds of getting anything back aren't significantly worse, yet somehow, I doubt there will be a flood of money in my mailbox anytime soon. >>
ZERO odds is not nearly as good as REMOTE odds.
Plus sending you $2 gets me ZERO enjoyment. Imagining lots of expensive coins for 24 hours gets me a lot of enjoyment.
Picking up the latest Heritage catalog and treating it like my personal wish-list gives me way more than $2 of enjoyment.
Imagining calling Legend tomorrow and saying: I'll take everything.
<<Assuming you can counter all of the hurdles associated with the practical execution of these ticket purchases, as the tickets are $2 per pick, that would cost you $350,447,020 to cover all 175,223,510 combinations. At a $550 million jackpot, that would be a pre-tax profit of $199,552,980 only if no one else wins. If one other person gets it, you'll split the pot and would then have lost $75,447,020.>>
Didn't realize the PB had increased to $2, been a while I guess.
I've always looked at these Lottery's with the big payouts as the price of an admission ticket to a Mental Disneyland.
Of course you're not going to win, but it's probably worth the price of admission to think about it for 24-48 hours.............
Retired Collector & Dealer in Major Mint Error Coins & Currency since the 1960's.Co-Author of Whitman's "100 Greatest U.S. Mint Error Coins", and the Error Coin Encyclopedia, Vols., III & IV. Retired Authenticator for Major Mint Errors for PCGS. A 49+-Year PNG Member...A full numismatist since 1972, retired in 2022
That was precisely what I was going to reply with, what are the odds of that? 1 in 175,223,510 are the current odds. Your chances would be pretty good if you purchased 175,223,510 different combinations. Is it possible to buy that many? How could one accomplish this? >>
It could be possible to do it, but you'd need quite the taskforce to accomplish it. The new machines which let you buy a ticket without having to go up to the counter at a gas station/etc. have a maximum of $20 per ticket and I'll make a generous round-trip estimate of 10 seconds to insert the $20 and receive the ticket at the end with 10 numbers. This would take approximately 200 years to buy, assuming working 24/7 at this rate and the machines don't run out of paper.
However, the Birthday Paradox falls into play here with randomly picked numbers - you'll end up receiving duplicate picks with this volume. To ensure you don't miss any number and don't overspend, the automated machines are out of the question: you would have to pre-select each combination manually.
Assuming you can counter all of the hurdles associated with the practical execution of these ticket purchases, as the tickets are $2 per pick, that would cost you $350,447,020 to cover all 175,223,510 combinations. At a $550 million jackpot, that would be a pre-tax profit of $199,552,980 only if no one else wins. If one other person gets it, you'll split the pot and would then have lost $75,447,020.
<< <i>1 in 175 million is less than the chances of me meeting my wife but I did >>
If the odds of meeting the person you married are over 1 in 175 million, practically nobody would be married. >>
The odds of marrying someone is probably 1 in 2 or so. The odds of meeting MY WIFE are 1 out of however many people there are in the United States that are female. If you knew my wife you would agree that I hit the jackpot
<< <i>The odds of meeting MY WIFE are 1 out of however many people there are in the United States that are female. >>
Actually, the odds of you meeting your wife are 1 out of however many people there are in the United States that are female that 1) you meet and 2) spend enough time with to actually consider worth marrying. That number is considerably less than the number of females in the US.
If each possible combination was on a 1 inch cube and were placed next to and on top of each other,the cubes would occupy a volume 40.3 ft. on each side.
$2 for a chance at $1/2 B and some change? Why not?
I would give most of the money away.
Great spirits have always encountered violent opposition from mediocre minds.-Albert Einstein
I told my wife to join her office pool for the $2 admission price because if THEY win and she did NOT join it would be an awful thing to have to go to work every day!!!
. i'd play if they'd keep drawing numbers until the system verified say 100-500 winners. giving the average person 200m-500 is plain stupid, although i don't know how to pre-determine whom plays or wins
wouldn't it make sense that more people would play if the odds of winning went up by drawing more numbers? .
I'm 41 and think I have better odds getting money out of the lottery than I do getting money out of social security. At least I'm not forced by law to buy lottery tickets and they cost a fraction of a percent of the money I've wasted giving it to the Feds.
"For every complex problem there is an answer that is clear, simple, and wrong." H.L. Mencken
I live in a non Powerball state, but have my ticket. I get it mailed to me for 26 draws. I have a premonition the last post in this thread will win it. No one else post. 15 minutes to draw.
That was precisely what I was going to reply with, what are the odds of that? 1 in 175,223,510 are the current odds. Your chances would be pretty good if you purchased 175,223,510 different combinations. Is it possible to buy that many? How could one accomplish this? >>
It could be possible to do it, but you'd need quite the taskforce to accomplish it. The new machines which let you buy a ticket without having to go up to the counter at a gas station/etc. have a maximum of $20 per ticket and I'll make a generous round-trip estimate of 10 seconds to insert the $20 and receive the ticket at the end with 10 numbers. This would take approximately 200 years to buy, assuming working 24/7 at this rate and the machines don't run out of paper.
However, the Birthday Paradox falls into play here with randomly picked numbers - you'll end up receiving duplicate picks with this volume. To ensure you don't miss any number and don't overspend, the automated machines are out of the question: you would have to pre-select each combination manually.
Assuming you can counter all of the hurdles associated with the practical execution of these ticket purchases, as the tickets are $2 per pick, that would cost you $350,447,020 to cover all 175,223,510 combinations. At a $550 million jackpot, that would be a pre-tax profit of $199,552,980 only if no one else wins. If one other person gets it, you'll split the pot and would then have lost $75,447,020.
So, I'd recommend against it >>
Would you hit a higher percentage of all of the possibilities by doing 175,223,510 easy picks one time from one machine than by spreading them out over 50,000 different machines?
<< <i>1 in 175 million is less than the chances of me meeting my wife but I did >>
If the odds of meeting the person you married are over 1 in 175 million, practically nobody would be married. >>
The odds of marrying someone is probably 1 in 2 or so. The odds of meeting MY WIFE are 1 out of however many people there are in the United States that are female. If you knew my wife you would agree that I hit the jackpot >>
I assume you could discard all of those under 21 and those over 55 so that shud up your odds.
Comments
<< <i>no and not planning to >>
Ya cant win if ya dont play!
I got my 10.................
1. I can afford to lose $20 or whatever.
2. It is FUN to imagine the winnings for 24 hours And paying $20 for that much fun is a good buy
Authorized dealer for PCGS, PCGS Currency, NGC, NCS, PMG, CAC. Member of the PNG, ANA. Member dealer of CoinPlex and CCE/FACTS as "CH5"
That was precisely what I was going to reply with, what are the odds of that?
1 in 175,223,510 are the current odds. Your chances would be pretty good if you purchased 175,223,510 different combinations.
Is it possible to buy that many? How could one accomplish this?
This HAS BEEN DONE in other lotteries. Naturally the groups are private, but there was a group that won this way in the Netherlands or some country like that.
NOTE: In the powerball you have to buy "in person" in most places, possibly all, so buying more than a few thousand tickets would be impossible due to time constraints.
Also remember that if you SPLIT THE WINNINGS you are going to be hating life after spending $300M+
<< <i>You also can't lose anything you would remember in a week if you play >>
A week later? I'm sure I would remember buying a ticket. And if you wouldn't remember, what good would having the winning ticket be, anyway?
<< <i>$2 is never going to be noticed by the people on this board. >>
In that case, it shouldn't be a problem to get everybody on the board to send me $2, should it? The odds of getting anything back aren't significantly worse, yet somehow, I doubt there will be a flood of money in my mailbox anytime soon.
<< <i><<Can't lose if you don't play.>>
That was precisely what I was going to reply with, what are the odds of that?
1 in 175,223,510 are the current odds. Your chances would be pretty good if you purchased 175,223,510 different combinations.
Is it possible to buy that many? How could one accomplish this? >>
It could be possible to do it, but you'd need quite the taskforce to accomplish it. The new machines which let you buy a ticket without having to go up to the counter at a gas station/etc. have a maximum of $20 per ticket and I'll make a generous round-trip estimate of 10 seconds to insert the $20 and receive the ticket at the end with 10 numbers. This would take approximately 200 years to buy, assuming working 24/7 at this rate and the machines don't run out of paper.
However, the Birthday Paradox falls into play here with randomly picked numbers - you'll end up receiving duplicate picks with this volume. To ensure you don't miss any number and don't overspend, the automated machines are out of the question: you would have to pre-select each combination manually.
Assuming you can counter all of the hurdles associated with the practical execution of these ticket purchases, as the tickets are $2 per pick, that would cost you $350,447,020 to cover all 175,223,510 combinations. At a $550 million jackpot, that would be a pre-tax profit of $199,552,980 only if no one else wins. If one other person gets it, you'll split the pot and would then have lost $75,447,020.
So, I'd recommend against it
<< <i>
<< <i>You also can't lose anything you would remember in a week if you play >>
A week later? I'm sure I would remember buying a ticket. And if you wouldn't remember, what good would having the winning ticket be, anyway?
<< <i>$2 is never going to be noticed by the people on this board. >>
In that case, it shouldn't be a problem to get everybody on the board to send me $2, should it? The odds of getting anything back aren't significantly worse, yet somehow, I doubt there will be a flood of money in my mailbox anytime soon. >>
ZERO odds is not nearly as good as REMOTE odds.
Plus sending you $2 gets me ZERO enjoyment. Imagining lots of expensive coins for 24 hours gets me a lot of enjoyment.
Picking up the latest Heritage catalog and treating it like my personal wish-list gives me way more than $2 of enjoyment.
Imagining calling Legend tomorrow and saying: I'll take everything.
That gives me a lot more than $2 in enjoyment
Didn't realize the PB had increased to $2, been a while I guess.
Member, Society of Silver Dollar Collectors.
Looking for PCGS AU58+ 1901-P, 1896-O, & 1894-O
<< <i>ZERO odds is not nearly as good as REMOTE odds. >>
If they're remote enough, it doesn't matter.
Odds of getting struck by lightning twice in your life: 1 in 9 million.
Odds of winning the powerball drawing: 1 in 175 million.
I've always looked at these Lottery's
with the big payouts as the price of
an admission ticket to a Mental Disneyland.
Of course you're not going to win, but
it's probably worth the price of admission
to think about it for 24-48 hours.............
for PCGS. A 49+-Year PNG Member...A full numismatist since 1972, retired in 2022
<< <i>
<< <i><<Can't lose if you don't play.>>
That was precisely what I was going to reply with, what are the odds of that?
1 in 175,223,510 are the current odds. Your chances would be pretty good if you purchased 175,223,510 different combinations.
Is it possible to buy that many? How could one accomplish this? >>
It could be possible to do it, but you'd need quite the taskforce to accomplish it. The new machines which let you buy a ticket without having to go up to the counter at a gas station/etc. have a maximum of $20 per ticket and I'll make a generous round-trip estimate of 10 seconds to insert the $20 and receive the ticket at the end with 10 numbers. This would take approximately 200 years to buy, assuming working 24/7 at this rate and the machines don't run out of paper.
However, the Birthday Paradox falls into play here with randomly picked numbers - you'll end up receiving duplicate picks with this volume. To ensure you don't miss any number and don't overspend, the automated machines are out of the question: you would have to pre-select each combination manually.
Assuming you can counter all of the hurdles associated with the practical execution of these ticket purchases, as the tickets are $2 per pick, that would cost you $350,447,020 to cover all 175,223,510 combinations. At a $550 million jackpot, that would be a pre-tax profit of $199,552,980 only if no one else wins. If one other person gets it, you'll split the pot and would then have lost $75,447,020.
So, I'd recommend against it >>
<< <i>
<< <i>ZERO odds is not nearly as good as REMOTE odds. >>
If they're remote enough, it doesn't matter.
Odds of getting struck by lightning twice in your life: 1 in 9 million.
Odds of winning the powerball drawing: 1 in 175 million. >>
It sure matters to the winner! 1 in 175 million is less than the chances of me meeting my wife but I did So I'm hoping to double down!
<< <i>1 in 175 million is less than the chances of me meeting my wife but I did >>
If the odds of meeting the person you married are over 1 in 175 million, practically nobody would be married.
In light of all the troubles chance might toss in my way I'll do my best to avoid being afflicted with a half billion clams.
<< <i>no and not planning to >>
I've always thought of the lottery as a voluntary "stupid" tax.
<< <i>
<< <i>1 in 175 million is less than the chances of me meeting my wife but I did >>
If the odds of meeting the person you married are over 1 in 175 million, practically nobody would be married. >>
The odds of marrying someone is probably 1 in 2 or so. The odds of meeting MY WIFE are 1 out of however many people there are in the United States that are female. If you knew my wife you would agree that I hit the jackpot
<< <i>Can't. In one of the 8 or so states that doesn't do Powerball. >>
Yeah, me too.
bob in Las Vegas
<< <i>The odds of meeting MY WIFE are 1 out of however many people there are in the United States that are female. >>
Actually, the odds of you meeting your wife are 1 out of however many people there are in the United States that are female that 1) you meet and 2) spend enough time with to actually consider worth marrying. That number is considerably less than the number of females in the US.
$2 for a chance at $1/2 B and some change? Why not?
I would give most of the money away.
Great spirits have always encountered violent opposition from mediocre minds.-Albert Einstein
Chris' Complete Lincoln Variety Set 1909-date
bob
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i'd play if they'd keep drawing numbers until the system verified say 100-500 winners. giving the average person 200m-500 is plain stupid, although i don't know how to pre-determine whom plays or wins
wouldn't it make sense that more people would play if the odds of winning went up by drawing more numbers?
.
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<< <i>
<< <i><<Can't lose if you don't play.>>
That was precisely what I was going to reply with, what are the odds of that?
1 in 175,223,510 are the current odds. Your chances would be pretty good if you purchased 175,223,510 different combinations.
Is it possible to buy that many? How could one accomplish this? >>
It could be possible to do it, but you'd need quite the taskforce to accomplish it. The new machines which let you buy a ticket without having to go up to the counter at a gas station/etc. have a maximum of $20 per ticket and I'll make a generous round-trip estimate of 10 seconds to insert the $20 and receive the ticket at the end with 10 numbers. This would take approximately 200 years to buy, assuming working 24/7 at this rate and the machines don't run out of paper.
However, the Birthday Paradox falls into play here with randomly picked numbers - you'll end up receiving duplicate picks with this volume. To ensure you don't miss any number and don't overspend, the automated machines are out of the question: you would have to pre-select each combination manually.
Assuming you can counter all of the hurdles associated with the practical execution of these ticket purchases, as the tickets are $2 per pick, that would cost you $350,447,020 to cover all 175,223,510 combinations. At a $550 million jackpot, that would be a pre-tax profit of $199,552,980 only if no one else wins. If one other person gets it, you'll split the pot and would then have lost $75,447,020.
So, I'd recommend against it >>
Would you hit a higher percentage of all of the possibilities by doing 175,223,510 easy picks one time from one machine than by spreading them out over 50,000 different machines?
MY COINS FOR SALE AT https://www.pcgs.com/setregistry/collectors-showcase/other/bajjerfans-coins-sale/3876
<< <i>
<< <i>
<< <i>1 in 175 million is less than the chances of me meeting my wife but I did >>
If the odds of meeting the person you married are over 1 in 175 million, practically nobody would be married. >>
The odds of marrying someone is probably 1 in 2 or so. The odds of meeting MY WIFE are 1 out of however many people there are in the United States that are female. If you knew my wife you would agree that I hit the jackpot >>
I assume you could discard all of those under 21 and those over 55 so that shud up your odds.
MY COINS FOR SALE AT https://www.pcgs.com/setregistry/collectors-showcase/other/bajjerfans-coins-sale/3876
<< <i>5 16 22 23 29 6 >>
If only u would have posted this a few hours ago..
Take it easy.....Lion