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Measuring Centering

Anyone have any methods to measure the centering? Eye-balling would only go so far. I posted the question on a differ thread and decided to start a new one rather than hijacking the other one.

EAMUS CATULI!

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Comments

  • SoFLPhillyFanSoFLPhillyFan Posts: 3,931 ✭✭

    Add the two sides together and divide one of the sides by the total. This is your percentage for that side.

    Example - Left side - 3mm
    Right side - 4mm
    Total - 7mm

    3 divided by 7 = .043 approximately

    Left side is 43%
  • GATOR5GATOR5 Posts: 654
    Zef-

    Grab a ruler a drafting ruler is best. Sixteenths will give you an idea. Measure left border then right add the two together then divide by either side and thats what your left with for that side minus a 100 thats the other.

    Hope that helps.

    Gator
  • KnucklesKnuckles Posts: 2,512 ✭✭✭
    Click Here

    For more simply type centering and hit Search! above all the message threads in the Sports Cards & Memorabilia forum.
    image
  • Stone193Stone193 Posts: 24,407 ✭✭✭✭✭
    You guys are making this too complicated.

    Just take the total width of the four sides and multiply by the negative inverse of the slope and divide by 16. Then take the reciprocal of the square root of the first side and subtract it from the cubed root of the remaining 3 sides and divide by 32. Finally take the quotient and place into the slope intercept format of
    y = mX + b – simultaneously solve both equations for the two sides.

    Simple, ez and totally ubiquitous.

    image
    Mike
  • SoFLPhillyFanSoFLPhillyFan Posts: 3,931 ✭✭
    Mike -

    If it's a die cut card with irregular sides I think "pi" goes in the equation somewhere.

    Preferably Dutch Apple. image
  • Have you ever turned the card upside down to get another perspective on the centering?
  • Stone193Stone193 Posts: 24,407 ✭✭✭✭✭


    << <i>Have you ever turned the card upside down to get another perspective on the centering? >>


    No
    But I have tried closing my eyes.

    image
    Mike
  • softparadesoftparade Posts: 9,276 ✭✭✭✭✭


    << <i>You guys are making this too complicated.

    Just take the total width of the four sides and multiply by the negative inverse of the slope and divide by 16. Then take the reciprocal of the square root of the first side and subtract it from the cubed root of the remaining 3 sides and divide by 32. Finally take the quotient and place into the slope intercept format of
    y = mX + b – simultaneously solve both equations for the two sides.

    Simple, ez and totally ubiquitous.

    image >>



    in other words ..... use your eyes slackers!!! image

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  • RipublicaninMassRipublicaninMass Posts: 10,051 ✭✭✭


    << <i>

    << <i>Have you ever turned the card upside down to get another perspective on the centering? >>


    No
    But I have tried closing my eyes.

    image >>



    Was that when you were a grader for PRO?
  • ctsoxfanctsoxfan Posts: 6,246 ✭✭
    You could always just slightly shave off the wider end of the card, so it looks perfectly centered. Then, ship it off to BGS.
    image
  • Stone193Stone193 Posts: 24,407 ✭✭✭✭✭


    << <i>

    << <i>

    << <i>Have you ever turned the card upside down to get another perspective on the centering? >>


    No
    But I have tried closing my eyes.

    image >>



    Was that when you were a grader for PRO? >>


    image
    Mike
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